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大整数乘法的分治法源码，在JDK1.51中运行-large integer multiplication of the divide-and-conquer method source code, to run in JDK1.51
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VC++ 分治法大整数乘法-VC++ divide and conquer large integer multiplication
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君主和殖民者们所成功运用的分而治之策略也可以运用到高效率的计算机算法的设计过程中。本章将首先介绍怎样在算法设计领域应用这一古老的策略，然后将利用这一策略解决如下问题：最小最大问题、矩阵乘法、残缺棋盘、排序、选择和一个计算几何问题——找出二维空间中距离最近的两个点。
本章给出了用来分析分而治之算法复杂性的数学方法，并通过推导最小最大问题和排序问题的复杂性下限来证明分而治-monarchy and colonialists who have successfully used the divid
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in this code we do the multiplication with divide and conquer method. it can be known dynamic programming
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矩阵乘法分治法实现。。C-Divide and conquer matrix multiplication implementation. . C++. . . . .
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Multiplication of two polynomial using divide and conquer method.
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用netbeans写的swing程序，写了非递归求两整数最大公因子、分治法求大整数乘法、动态规划求最长公共子串，集合划分问题。 -Netbeans swing with written procedures, write a non recursive find the greatest common factor of two integers, divide and conquer seek large integer multiplication, dynamic programming
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Strassen矩阵乘法
分治法 矩阵乘法
时间复杂度O(n^2.81)-Strassen matrix multiplication, divide and conquer matrix multiplication time complexity O (n ^ 2.81)
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分治法实现的大整数乘法。是学习分治算法策略的很好的范例。-Sub-rule method to achieve the large-integer multiplication. Is a good example of learning the strategy of divide and conquer algorithm.
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分治法大整数乘法课件
概述：算法概要、算法效率
合并排序
快速排序
折半查找
大整数乘法
Strassen 矩阵乘法
分治法解凸包
-Divide and conquer integer multiplication courseware
about the function and some problems very effective way to solve the that serious .I think it will be ok!
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分治法实现大整数乘法，其实应该用数组来保存大整数的，再考虑如何去完善这个程序。但分治算法的核心思想已经尽在其中了。-Divide and conquer method for large integer multiplication
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大整数乘法，编译通过，采用的是分治法，绝对正确-Large integer multiplication, compiled by the divide and conquer, absolutely right.
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Strassen矩阵乘法，运用分治法，书上资料，编译通过-Strassen matrix multiplication using divide-and-conquer method book, compiled by
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分治法矩阵相乘函数，优化时间复杂度，简单递归调用-Divide and conquer matrix multiplication function
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此为对分治法大整数相乘的一个改进，能够给对刚开始学习算法的人一个了解的机会-This is an improved large integer multiplication of divide-and-conquer method to the beginning of the learning algorithm an understanding of the opportunity
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算法分析与设计
用递归分治算法解决大整数乘积问题（java源码）-Algorithm Analysis and Design
Recursive divide and conquer algorithm to solve the problem of large integer
multiplication.
(Java source code)
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计算1万位以上的大整数乘法，有蛮力法和分治法-Calculation 10,000 more than the large integer multiplication with brute force method and the divide and conquer
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分治法求大整数乘法 只能支持256位乘法而已，不过已经完整实现了分治法，而且可以支持有符号的数-Divide and conquer method for large integer multiplication multiply it can only support 256, but has been completely realized divide and conquer, and can support a number of symbols
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矩阵乘法（分治法） 设A 和 B 是两个n * n阶矩阵，求它们两的乘积矩阵C。-Matrix multiplication (divide and conquer) Let A and B be two n* n order matrix, find the product of their two matrix C.
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实现大整数相乘，时间复杂度n(logn),c++源码-Achieve a large integer multiplication, time complexity n (logn), c++ source
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